take_mut

Intended to allow taking a T from a &mut T temporarily

Latest version: 0.2.2 registry icon
Maintenance score
0
Safety score
0
Popularity score
71
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Security
  Vulnerabilities
Version Suggest Low Medium High Critical
0.2.2 0 0 0 0 0
0.2.1 0 0 0 0 0
0.2.0 0 0 0 0 0
0.1.3 0 0 0 0 0
0.1.2 0 0 0 0 0
0.1.1 0 0 0 0 0
0.1.0 0 0 0 0 0

Stability
Latest release:

0.2.2 - This version may not be safe as it has not been updated for a long time. Find out if your coding project uses this component and get notified of any reported security vulnerabilities with Meterian-X Open Source Security Platform

Licensing

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MIT   -   MIT License

Not a wildcard

Not proprietary

OSI Compliant



take_mut

This crate provides (at this time) a single function, take().

take() allows for taking T out of a &mut T, doing anything with it including consuming it, and producing another T to put back in the &mut T.

During take(), if a panic occurs, the entire process will be exited, as there's no valid T to put back into the &mut T.

Contrast with std::mem::replace(), which allows for putting a different T into a &mut T, but requiring the new T to be available before being able to consume the old T.

Example

struct Foo;
let mut foo = Foo;
take_mut::take(&mut foo, |foo| {
    // Can now consume the Foo, and provide a new value later
    drop(foo);
    // Do more stuff
    Foo // Return new Foo from closure, which goes back into the &mut Foo
});